w/w^2-3w-40-7/w+5

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Solution for w/w^2-3w-40-7/w+5 equation:


D( w )

w^2 = 0

w = 0

w^2 = 0

w^2 = 0

1*w^2 = 0 // : 1

w^2 = 0

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w/(w^2)-(3*w)-(7/w)-40+5 = 0

w/(w^2)-3*w-7*w^-1-40+5 = 0

-3*w^1-6*w^-1-35*w^0 = 0

(-3*w^2-35*w^1-6*w^0)/(w^1) = 0 // * w^2

w^1*(-3*w^2-35*w^1-6*w^0) = 0

w^1

-3*w^2-35*w-6 = 0

-3*w^2-35*w-6 = 0

DELTA = (-35)^2-(-6*(-3)*4)

DELTA = 1153

DELTA > 0

w = (1153^(1/2)+35)/(-3*2) or w = (35-1153^(1/2))/(-3*2)

w = (1153^(1/2)+35)/(-6) or w = (35-1153^(1/2))/(-6)

w in { (1153^(1/2)+35)/(-6), (35-1153^(1/2))/(-6)}

w in { (1153^(1/2)+35)/(-6), (35-1153^(1/2))/(-6) }

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